Answer
see table
Work Step by Step
$\bf{\text{Solution Outline:}}$
Complete the table by substituting the given value of the variable in the given equation, $
3x+2y=10
.$
$\bf{\text{Solution Details:}}$
If $
x=0
,$ then
\begin{array}{l}\require{cancel}
3x+2y=10
\\\\
3(0)+2y=10
\\\\
0+2y=10
\\\\
2y=10
\\\\
y=\dfrac{10}{2}
\\\\
y=5
.\end{array}
If $
y=0
,$ then
\begin{array}{l}\require{cancel}
3x+2y=10
\\\\
3x+2(0)=10
\\\\
3x+0=10
\\\\
3x=10
\\\\
x=\dfrac{10}{3}
.\end{array}
If $
x=2
,$ then
\begin{array}{l}\require{cancel}
3x+2y=10
\\\\
3(2)+2y=10
\\\\
6+2y=10
\\\\
2y=10-6
\\\\
2y=4
\\\\
y=\dfrac{4}{2}
\\\\
y=2
.\end{array}
If $
y=-2
,$ then
\begin{array}{l}\require{cancel}
3x+2y=10
\\\\
3x+2(-2)=10
\\\\
3x-4=10
\\\\
3x=10+4
\\\\
3x=14
\\\\
x=\dfrac{14}{3}
.\end{array}