Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Chapters R-2 - Cumulative Review Exercises: 13

Answer

$z=\dfrac{7}{6}$

Work Step by Step

Using the properties of equality, the solution to the given equation, $ 2z-5+3z=4-(z+2) $ is \begin{array}{l}\require{cancel} 2z-5+3z=4-z-2 \\\\ 2z+3z+z=4-2+5 \\\\ 6z=7 \\\\ z=\dfrac{7}{6} .\end{array}
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