## Intermediate Algebra (12th Edition)

$\left\{ x| x=24 \right\}$
Multiplying both sides by the $LCD= 12$, the given equation, $\dfrac{x}{4}-\dfrac{2x}{3}=-10 ,$ is equivalent to \begin{array}{l}\require{cancel} 3(x)-4(2x)=12(-10) \\\\ 3x-8x=-120 \\\\ -5x=-120 \\\\ x=\dfrac{-120}{-5} \\\\ x=24 .\end{array} Hence, the solution is $\left\{ x| x=24 \right\} .$