## Intermediate Algebra (12th Edition)

Published by Pearson

# Chapter 1 - Section 1.5 - Linear Inequalities in One Variable - 1.5 Exercises: 15

#### Answer

$(-\infty, -40)$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given inequality, $-\dfrac{3}{4}x\ge30 ,$ use the properties of inequality. For the interval notation, use a parenthesis for the symbols $\lt$ or $\gt.$ Use a bracket for the symbols $\le$ or $\ge.$ For graphing inequalities, use a hollowed dot for the symbols $\lt$ or $\gt.$ Use a solid dot for the symbols $\le$ or $\ge.$ $\bf{\text{Solution Details:}}$ Using the properties of inequality, the inequality above is equivalent to \begin{array}{l}\require{cancel} 4\left(-\dfrac{3}{4}x\right)\ge4(30) \\\\ -3x\ge120 .\end{array} Dividing both sides by a negative number (and consequently reversing the sign), the inequality above is equivalent to \begin{array}{l}\require{cancel} x\le\dfrac{120}{-3} \\\\ x\le-40 .\end{array} The red graph is the graph of the solution set. In interval notation, the solution set is $(-\infty, -40) .$

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