Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Section 1.2 - Formulas and Percent - 1.2 Exercises - Page 62: 34

Answer

$y=\dfrac{8}{3}x-\dfrac{4}{3}$

Work Step by Step

Using the properties of equality, in terms of $ y ,$ the given equation, $ 8x-3y=4 ,$ is equivalent to \begin{array}{l}\require{cancel} -3y=-8x+4 \\\\ y=\dfrac{-8}{-3}x+\dfrac{4}{-3} \\\\ y=\dfrac{8}{3}x-\dfrac{4}{3} .\end{array}
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