## Intermediate Algebra (12th Edition)

$y=\dfrac{8}{3}x-\dfrac{4}{3}$
Using the properties of equality, in terms of $y ,$ the given equation, $8x-3y=4 ,$ is equivalent to \begin{array}{l}\require{cancel} -3y=-8x+4 \\\\ y=\dfrac{-8}{-3}x+\dfrac{4}{-3} \\\\ y=\dfrac{8}{3}x-\dfrac{4}{3} .\end{array}