Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Section 1.2 - Formulas and Percent - 1.2 Exercises: 18

Answer

$F=\dfrac{9}{5}C+32$

Work Step by Step

Using the properties of equality, in terms of $ F ,$ the given formula, $ C=\dfrac{5}{9}(F-32) ,$ is equivalent to \begin{array}{l}\require{cancel} 9C=5(F-32) \\\\ 9C=5F-160 \\\\ 9C+160=5F \\\\ \dfrac{9C+160}{5}=F \\\\ \dfrac{9}{5}C+32=F \\\\ F=\dfrac{9}{5}C+32 .\end{array}
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