## Intermediate Algebra (12th Edition)

1. Given: $\frac{2x + 5}{5} = \frac{3x + 1}{2} + \frac{-x + 8}{16}$ 2. Multiply by LCD (80): 80($\frac{2x + 5}{5}) = ( \frac{3x + 1}{2} + \frac{-x + 8}{16}$)80 3. Use distributive property to multiply: 16(2x + 5) = 40(3x + 1) + 5(-x + 8) 32x + 80 = 120x + 40 - 5x + 40 4. Add and subtract: -83x = 0 5. Divide: x = 0 6. Check: $\frac{2*0 + 5}{5} = \frac{3*0 + 1}{2} + \frac{-0 + 8}{16}$ 1 = 1, so 0 is a solution of the equation.