## Intermediate Algebra (12th Edition)

1. Given: $\frac{4x + 1}{3} = \frac{x + 5}{6} + \frac{x - 3}{6}$ 2. Multiply by LCD (6): 6($\frac{4x + 1}{3}) = (\frac{x + 5}{6} + \frac{x - 3}{6}$)6 3. Use distributive property to multiply: 2(4x + 1) = (x + 5) + (x - 3) 8x + 2 = 2x + 2 4. Add and subtract: 6x = 0 5. Divide: x = 0 6. Check: $\frac{4*0 + 1}{3} = \frac{0 + 5}{6} + \frac{0 - 3}{6}$ 1/3 = 1/3, so 0 is a solution of the equation.