## Intermediate Algebra (12th Edition)

Published by Pearson

# Chapter 1 - Section 1.1 - Linear Equations in One Variable - 1.1 Exercises: 65

x = 3

#### Work Step by Step

1. Given: $\frac{x - 10}{5} + \frac{2}{5}$ = -$\frac{x}{3}$ 2. Multiply by LCD (15): 15($\frac{x - 10}{5} + \frac{2}{5}$) = (-$\frac{x}{3}$)15 3. Use distributive property to multiply: 3(x - 10) + 3(2) = -5x 3x - 30 + 6 = -5x 4. Add and subtract: 8x = 24 5. Divide: x = 3 6. Check: $\frac{3 - 10}{5} + \frac{3}{5}$ = -$\frac{3}{3}$ -1 = -1, so 3 is a solution of the equation.

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