Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Mixed Review Exercises: 4

Answer

$x=0$

Work Step by Step

Using the properties of equality, the given equation, $ \dfrac{4x+2}{4}+\dfrac{3x-1}{8}=\dfrac{x+6}{16} ,$ is equivalent to \begin{array}{l}\require{cancel} 16\left( \dfrac{4x+2}{4}+\dfrac{3x-1}{8} \right) =\left( \dfrac{x+6}{16} \right)16 \\\\ 4(4x+2)+2(3x-1)=(x+6)(1) \\\\ 16x+8+6x-2=x+6 \\\\ 16x+6x-x=6-8+2 \\\\ 9x=0 \\\\ x=\dfrac{0}{9} \\\\ x=0 .\end{array}
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