Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Mixed Review Exercises: 2

Answer

$k=\dfrac{6r-bt}{a}$

Work Step by Step

Using the properties of equality, in terms of $ k ,$ the given equation, $ ak+bt=6r ,$ is equivalent to \begin{array}{l}\require{cancel} ak=6r-bt \\\\ k=\dfrac{6r-bt}{a} .\end{array}
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