Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 4 - Vector Spaces - 4.1 Vectors in Rn - 4.1 Exercises - Page 153: 33

Answer

$$w=(\frac{1}{2},-\frac{7}{2},-\frac{9}{2},2)$$

Work Step by Step

Let $u=(1,-1,0,,1)$, $v=(0,2,3,-1)$, we have $$w=\frac{1}{2}(u-3v)=\frac{1}{2}((1,-1,0,1)-3(0,2,3,-1))\\ =\frac{1}{2}((1,-1,0,1)-(0,6,9,-3))\\ =\frac{1}{2}(1,-7,-9,4)=(\frac{1}{2},-\frac{7}{2},-\frac{9}{2},2)$$
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