Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 4 - Vector Spaces - 4.1 Vectors in Rn - 4.1 Exercises - Page 153: 18

Answer

(a) $4 v=4(3,-2)=(12,-8) $ (b) $-\frac{1}{2} v=-\frac{1}{2}(3,-2)=\left(-\frac{3}{2}, 1\right)$ (c) $0 v=0(3,-2)=(0,0)$

Work Step by Step

(a) $4 v=4(3,-2)=(12,-8) $ (b) $-\frac{1}{2} v=-\frac{1}{2}(3,-2)=\left(-\frac{3}{2}, 1\right)$ (c) $0 v=0(3,-2)=(0,0)$
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