Chapter 1 - Systems of Linear Equations - Review Exercises - Page 35: 20

$x=0.6$ $y=0.5$ $(0.6,0.5)$

$0.2x -0.1y=0.07$ $0.4x-0.5y=-0.01$ Multiply the first equation by $-2$. $-0.4x+0.2y=-0.14$ $0.4x-0.5y=-0.01$ Eliminate the $x$-variable by addition of the two equations. $-0.3y=-0.15$ $y=0.5$ Substitute for $y$ and solve for $x$. $0.2x-0.1\times0.5=0.07$ $0.2x=0.12$ $x=0.6$