Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 1 - Systems of Linear Equations - 1.1 Introduction to Systems of Linear Equations - 1.1 Exercises: 42

Answer

{$(x_1,x_2)|4x_1+x_2=0$}

Work Step by Step

$\frac{2}{3}x_1+\frac{1}{6}x_2=0$ $4x_1+x_2=0$ Express $x_2$ in terms of $x_1$ $x_2= -4x_1$ Substitute for $x_2$ in the first equation. $\frac{2}{3}x_1+\frac{1}{6}(-4x_1)=0$ $\frac{2}{3}x_1-\frac{4}{6}x_1=0$ $\rightarrow$ Multiply by 6 to remove fractions. $4x_1-4x_1=0$ $\rightarrow$ This expression is always true and therefore any pair of values which satisfy 1st or 2nd equation is a possible solution.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.