Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.5 Polynomials and Factoring - R.5 Exercise Set: 30

Answer

$(t-2)(t^2-5)$

Work Step by Step

Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to \begin{array}{l}\require{cancel} t^3-2t^2-5t+10 \\\\= (t^3-2t^2)-(5t-10) .\end{array} Factoring the $GCF$ in each group results to \begin{array}{l}\require{cancel} (t^3-2t^2)-(5t-10) \\\\= t^2(t-2)-5(t-2) .\end{array} Factoring the $GCF= (t-2) $ of the entire expression above results to \begin{array}{l}\require{cancel} (t-2)(t^2-5) .\end{array}
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