Answer
$(n-2)(m+3)$
Work Step by Step
Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to
\begin{array}{l}\require{cancel}
mn-2m+3n-6
\\\\=
(mn-2m)+(3n-6)
.\end{array}
Factoring the $GCF$ in each group results to
\begin{array}{l}\require{cancel}
(mn-2m)+(3n-6)
\\\\=
m(n-2)+3(n-2)
.\end{array}
Factoring the $GCF=
(n-2)
$ of the entire expression above results to
\begin{array}{l}\require{cancel}
(n-2)(m+3)
.\end{array}
