Answer
$\left\{y|y\ge-\dfrac{8}{3} \right\}
\text{ or }
\left[ -\dfrac{8}{3},\infty \right)
$
Work Step by Step
Using the properties of inequality, the given inequality, $
2-6y\le18
,$ is equivalent to
\begin{array}{l}\require{cancel}
-6y\le18-2
\\\\
-6y\le16
\\\\
y\ge\dfrac{16}{-6}
\\\\
y\ge-\dfrac{8}{3}
.\end{array}
Hence, the solution is $
\left\{y|y\ge-\dfrac{8}{3} \right\}
\text{ or }
\left[ -\dfrac{8}{3},\infty \right)
.$
