## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$z=-\dfrac{16}{3}$
Using the properties of equality, the value of the variable that satisfies the given expression, $\dfrac{2}{3}=-\dfrac{z}{8} ,$ is \begin{array}{l}\require{cancel} \dfrac{z}{8}=-\dfrac{2}{3} \\\\ 8\left( \dfrac{z}{8} \right)=-\dfrac{2}{3}(8) \\\\ z=-\dfrac{16}{3} .\end{array}