Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.1 Introduction to Algebraic Expressions - R.1 Exercise Set - Page 939: 82

Answer

$r-5$

Work Step by Step

Removing the grouping symbols and then combining like terms, the given expression, $ 4r-(3r+5) ,$ simplifies to \begin{array}{l}\require{cancel} 4r-3r-5 \\\\= (4r-3r)-5 \\\\= r-5 .\end{array}
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