Answer
$|x+4|\lt3$
Work Step by Step
Halfway between the boundaries of the given graph, $-7$ and $-1,$ is $-4.$ From $-4,$ the points on the graph represent all numbers that are less than $3$ units away. Hence, the given graph is equivalent to
\begin{array}{l}\require{cancel}
|x-(-4)|\lt3
\\\\
|x+4|\lt3
.\end{array}