Answer
$|x|\ge6$
Work Step by Step
Since for any $c\gt0$, $|x|\gt c$ implies $x\gt c \text{ or } x\lt-c$ (which is equivalent to $|x|\ge c$ implies $x\ge c \text{ or } x\le-c$), the given inequality, $
x\le-6 \text{ or } 6\le x
,$ is equivalent to $
|x|\ge6
.$
