Answer
Choice I
Work Step by Step
Using "or," or the union of sets, the combined solutions of the given inequality
\begin{array}{l}\require{cancel}
\{x|x\le2\} \text{ }or\text{ } \{x|x\ge-2\}
,\end{array}
is the graph consisting of all real numbers. Hence, $\text{
Choice I
.}$