Answer
$0$
Work Step by Step
Subtracting the numerators and copying the denominator, the given expression, $
\dfrac{3a^2+7}{a^2-2a-8}-\dfrac{7+3a^2}{a^2-2a-8}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{3a^2+7-(7+3a^2)}{a^2-2a-8}
\\\\=
\dfrac{3a^2+7-7-3a^2}{a^2-2a-8}
\\\\=
\dfrac{0}{a^2-2a-8}
\\\\=
0
.\end{array}