Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 6 - Rational Expressions and Equations - 6.3 Addition, Subtraction, and Least Common Denominators - 6.3 Exercise Set - Page 393: 23

Answer

$0$

Work Step by Step

Adding the numerators and copying the denominator, the given expression, $ \dfrac{t^2-5t}{t-1}+\dfrac{5t-t^2}{t-1} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{t^2-5t+5t-t^2}{t-1} \\\\= \dfrac{0}{t-1} \\\\= 0 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.