Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 6 - Rational Expressions and Equations - 6.3 Addition, Subtraction, and Least Common Denominators - 6.3 Exercise Set - Page 393: 20

Answer

$x+2$

Work Step by Step

Adding the numerators and copying the denominator, the given expression, $ \dfrac{x^2}{x+5}+\dfrac{7x+10}{x+5} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{x^2+7x+10}{x+5} \\\\= \dfrac{(x+5)(x+2)}{x+5} \\\\= \dfrac{(\cancel{x+5})(x+2)}{\cancel{x+5}} \\\\= x+2 .\end{array}
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