Answer
$6$
Work Step by Step
Adding the numerators and copying the denominator, the given expression, $
\dfrac{5x+7}{x+3}+\dfrac{x+11}{x+3}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{5x+7+x+11}{x+3}
\\\\=
\dfrac{6x+18}{x+3}
\\\\=
\dfrac{6(x+3)}{x+3}
\\\\=
\dfrac{6(\cancel{x+3})}{\cancel{x+3}}
\\\\=
6
.\end{array}