Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 6 - Rational Expressions and Equations - 6.3 Addition, Subtraction, and Least Common Denominators - 6.3 Exercise Set - Page 393: 14

Answer

$\dfrac{t+4}{4t}$

Work Step by Step

Subtracting the numerators and copying the denominator, the given expression, $ \dfrac{5+3t}{4t}-\dfrac{2t+1}{4t} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{5+3t-(2t+1)}{4t} \\\\= \dfrac{5+3t-2t-1}{4t} \\\\= \dfrac{t+4}{4t} .\end{array}
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