Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - Mid-Chapter Review - Mixed Review: 6

Answer

$(x+3)(x^2+2)$

Work Step by Step

Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to \begin{array}{l}\require{cancel} x^3+3x^2+2x+6 \\\\= (x^3+3x^2)+(2x+6) .\end{array} Factoring the $GCF$ in each group results to \begin{array}{l}\require{cancel} x^2(x+3)+2(x+3) .\end{array} Factoring the $GCF= (x+3) $ of the entire expression above results to \begin{array}{l}\require{cancel} (x+3)(x^2+2) .\end{array}
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