Answer
$(x+5)(x+1)(x-1)$
Work Step by Step
Using factoring by grouping, the factored form of the given expression, $
x^3+5x^2-x-5
,$
\begin{array}{l}
(x^3+5x^2)-(x+5)
\\\\=
x^2(x+5)-(x+5)
\\\\=
(x+5)(x^2-1)
.\end{array}
Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of $2$ squares, then the factored form of the expression, $
(x+5)(x^2-1)
$, is
\begin{array}{l}
(x+5)(x+1)(x-1)
.\end{array}
