Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.6 Factoring: A General Strategy - 5.6 Exercise Set - Page 344: 39

Answer

$(x+1)(x+y)$

Work Step by Step

Using factoring by grouping, the factored form of the given expression, $ x^2+x+xy+y ,$ \begin{array}{l} (x^2+x)+(xy+y) \\\\= x(x+1)+y(x+1) \\\\= (x+1)(x+y) .\end{array}
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