## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(2t+1)(4t^2-2t+1)$
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of $2$ cubes, then the factored form of the given expression, $8t^3+1$ is \begin{array}{l} (2t+1)[(2t)^2-(2t)(1)+(1)^2] \\\\= (2t+1)(4t^2-2t+1) .\end{array}