Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.3 Factoring Trinomials of the Type ax2+bx+c - 5.3 Exercise Set: 23

Answer

prime

Work Step by Step

Rearranging the terms, the given expression is equivalent to \begin{array}{l}\require{cancel} 4+6t^2-13t \\\\= 6t^2-13t+4 .\end{array} Using the factoring of trinomials in the form $ax^2+bx+c,$ the $\text{ expression }$ \begin{array}{l}\require{cancel} 6t^2-13t+4 \end{array} has $ac= 6(4)=24 $ and $b= -13 .$ There are no two numbers with a product of $c$ and a sum of $b.$ Hence, the expression is $\text{ prime .}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.