Answer
$16y^6-40y^3+25$
Work Step by Step
Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the product of the given expression, $
(4y^3-5)^2
,$ is
\begin{array}{l}\require{cancel}
(4y^3)^2+2(4y^3)(-5)+(-5)^2
\\\\=
16y^6-40y^3+25
.\end{array}