Answer
$49x^2+14x+1$
Work Step by Step
Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the product of the given expression, $
(7x+1)^2
,$ is
\begin{array}{l}\require{cancel}
(7x)^2+2(7x)(1)+(1)^2
\\\\=
49x^2+14x+1
.\end{array}
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