Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Connecting: The Concepts - Exercises - Page 243: 9

Answer

$\dfrac{a^{15}}{b^{20}}$

Work Step by Step

Use the rule $\left(\dfrac{a}{b}\right)^m =\dfrac{a^m}{b^m}$ to obtain: $\left(\dfrac{a^3}{b^4}\right)^5=\dfrac{(a^3)^5}{(b^4)^5}$ Use the rule $(a^m)^n=a^{mn}$ to obtain: $\dfrac{(a^3)^5}{(b^4)^5}=\dfrac{a^{3(5)}}{b^{4(5)}}=\dfrac{a^{15}}{b^{20}}$
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