Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.7 Polynomials in Several Variables - 4.7 Exercise Set - Page 284: 52

Answer

$12x^2y^2+2xy-2$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of $2$ binomials, the given expression, $ (3xy-1)(4xy+2) ,$ simplifies to \begin{array}{l}\require{cancel} 3xy(4xy)+3xy(2)-1(4xy)-1(2) \\\\= 12x^2y^2+6xy-4xy-2 \\\\= 12x^2y^2+2xy-2 .\end{array}
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