Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 114

Answer

$9,951$

Work Step by Step

Since $93=100-7$ and $107=100+7$, then $93 \times 107 = (100-7)(100+7)$. Use the formula $(a-b)(a+b)=a^2-b^2$ with $a=20$ and $b=2$ to obtain: $=100^2-7^2 \\=10,000-49 \\=9,951$
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