Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 113

Answer

$396$

Work Step by Step

Since $18=20-2$ and $22=20+2$, then $18 \times 22 = (20-2)(20+2)$. Use the formula $(a-b)(a+b)=a^2-b^2$ with $a=20$ and $b=2$ to obtain: $=20^2-2^2 \\=400-4 \\=396$
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