Answer
$16x^4-81$
Work Step by Step
Use the formula $(a+b)(a-b)$ to multiply the last 2 factors to obtain:
$=(4x^2+9)[(2x)^2-3^2]
\\=(4x^2+9)(4x^2-9)$
Use the same formula again with $a=4x^2$ and $b=9$ to obtain:
$=(4x^2)^2-9^2
\\=16x^4-81$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set - Page 278: 107
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