Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 27

Answer

$t^2-4t+4$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $ (t-2)^2 $, is equivalent to \begin{array}{l}\require{cancel} (t)^2+2(t)(-2)+(-2)^2 \\\\= t^2-4t+4 .\end{array}
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