Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set - Page 276: 25

Answer

$1-25t^6$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the given expression, $ (1-5t^3)(1+5t^3) $, is equivalent to \begin{array}{l}\require{cancel} (1)^2-(5t^3)^2 \\\\= 1-25t^6 .\end{array}
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