Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.5 Multiplication of Polynomials - 4.5 Exercise Set: 64

Answer

$5a^5+17a^3-a^2-12a-4$

Work Step by Step

Using the Distributive Property, the product of the given expression, $ (a^2+4)(5a^3-3a-1) ,$ is \begin{array}{l}\require{cancel} a^2(5a^3)+a^2(-3a)+a^2(-1)+4(5a^3)+4(-3a)+4(-1) \\\\= 5a^5-3a^3-a^2+20a^3-12a-4 \\\\= 5a^5+(-3a^3+20a^3)-a^2-12a-4 \\\\= 5a^5+17a^3-a^2-12a-4 .\end{array}
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