Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.

Published by Pearson

ISBN 10: 0-32184-874-8

ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.2 Negative Exponents and Scientific Notations - 4.2 Exercise Set - Page 245: 123

Answer

$5$

Work Step by Step

The given expression, $ 24\div6\cdot2-3[4(3-1)-7] $, simplifies to \begin{array}{l} 24\div6\cdot2-3[4(2)-7] \\\\= 24\div6\cdot2-3[8-7] \\\\= 24\div6\cdot2-3[1] \\\\= 24\div6\cdot2-3 \\\\= 4\cdot2-3 \\\\= 8-3 \\\\= 5 .\end{array}

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