Answer
see explanation
Work Step by Step
If $t=2$, then the expression $
\dfrac{t^6}{t^2}
$ evaluates to
\begin{array}{l}\require{cancel}
\dfrac{2^6}{2^2}
\\\\=
\dfrac{64}{4}
\\\\=
16
,\end{array}
and the expression $
t^3
$ evaluates to
\begin{array}{l}
2^3
\\\\=
8
.\end{array}
Hence, $
\dfrac{t^6}{t^2}
\ne
t^3
$.
