Answer
$5p$
Work Step by Step
Since $a^x\cdot a^y=a^{x+y}$, then the given expression, $
(5p)^0\cdot (5p)^{1}
$, simplifies to
\begin{array}{l}\require{cancel}
(5p)^{0+1}
\\\\=
(5p)^{1}
.\end{array}
Since $(ab)^x=a^xb^x$, then the expression above simplifies to
\begin{array}{l}\require{cancel}
5^1p^1
\\\\=
5p
.\end{array}