Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set: 22

Answer

$(2t)^{25}$

Work Step by Step

Since $a^x\cdot a^y=a^{x+y}$, then the given expression, $ (2t)^8\cdot (2t)^{17} $, simplifies to \begin{array}{l}\require{cancel} (2t)^{8+17} \\\\= (2t)^{25} .\end{array}
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