Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - Study Summary - Practice Exercises: 13

Answer

$y-6=\frac{1}{4}(x+1)$

Work Step by Step

RECALL: The point-slope form of a line's equation is $y-y_1=m(x-x_1)$, where $m$=slope and $(x_1, y_1)$ is a point on the line. The given line has a slope of $\frac{1}{4}$ and contains the point $(-1, 6)$. Thus, the point-slope form of its equation is: $y-6=\frac{1}{4}[x-(-1)] \\y-6=\frac{1}{4}(x+1)$
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