Answer
$y=2x-1$
Work Step by Step
Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the Two-Point Form, then the equation of the line passing through the given points, $(
-1,-3
)\text{ and }(
-4,-9
)$, is
\begin{array}{l}
y-(-3)=\dfrac{-3-(-9)}{-1-(-4)}(x-(-1))
\\\\
y+3=\dfrac{-3+9}{-1+4}(x+1)
\\\\
y+3=\dfrac{6}{3}(x+1)
\\\\
y+3=2(x+1)
\\\\
y+3=2x+2
\\\\
y=2x+2-3
\\\\
y=2x-1
.\end{array}