Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.7 Point-Slope Form and Equations of Lines - 3.7 Exercise Set - Page 219: 69

Answer

$y=\dfrac{9}{2}x-9.4$

Work Step by Step

Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the Two-Point Form, then the equation of the line passing through the given points, $( 1.2,-4 )\text{ and }( 3.2,5 )$, is \begin{array}{l} y-(-4)=\dfrac{-4-5}{1.2-3.2}(x-1.2) \\\\ y+4=\dfrac{-9}{-2}(x-1.2) \\\\ y+4=\dfrac{9}{2}(x-1.2) \\\\ y+4=\dfrac{9}{2}x-5.4 \\\\ y=\dfrac{9}{2}x-5.4-4 \\\\ y=\dfrac{9}{2}x-9.4 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.